8x/x^2+2x-3

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Solution for 8x/x^2+2x-3 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x+(8*x)/(x^2)-3 = 0

2*x^1+8*x^-1-3*x^0 = 0

(2*x^2-3*x^1+8*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^2-3*x^1+8*x^0) = 0

x^1

2*x^2-3*x+8 = 0

2*x^2-3*x+8 = 0

DELTA = (-3)^2-(2*4*8)

DELTA = -55

DELTA < 0

x in { } 

x belongs to the empty set

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